POLAR EQUATIONS
Example 1:
Change the rectangular equation
to polar form. Write the polar equation as r in terms of
.
Knowing that
and
, we can convert as follows:
Now, we must write r in terms of
.
In this case, this is done by factoring. We will factor r out of both expressions to get
Using the Zero Product Principle we get
or
.
The graph of
is the pole.
Since the pole is already included in
(Hint: Let
= 0), we don't need
.
Therefore, all we need to do is write
in terms of
.
That is,
.
Thus, the polar form of
is
.
WARNING:
It is incorrect to divide both sides of the equation
by r to arrive at the solution
!!! From algebra you should remember that we cannot divide by a variable UNLESS we are certain that this variable will NEVER take on the value of 0. In our case, we find thatr actually can take on this value!
Example 2:
Change the rectangular equation
to polar form. Write the polar equation as r in terms of
.
Knowing that
and
, we can convert as follows:
Now, we must write r in terms of
. In this case, this is done by factoring. We will factor r out of both expressions to get
Next, we will factor r out of both expressions as follows:
Using the Zero Product Principle we get
or
The graph of
is the pole. Since the pole is already included in the graph of
(Hint: Let
= 0), we don't need
.
Therefore, all we need to do is write
in terms of
.
That is,
.
Thus, the polar form of
is
.
Example 3:
Change the rectangular equation
to polar form. Write the polar equation as r in terms of
.
Knowing that
, we can convert as follows:
It may seem to you that we have accomplished our goal, that is, we converted the rectangular equation to polar form. However, it is standard procedure to write r in terms of
.
Now, we must write r in terms of
. In this case, this is done by factoring as follows:
and
(Notice that we are dealing with a Difference of Squares).
Using the Zero Product Principle we get
or
Next, we will rewrite the polar equation as r in terms of
.
That is,
or
Either of the two equations is correct. However, it is accepted mathematical practice to let the positive value,
, represent
in polar form.
Remember that the variables in a polar equation are r and
! Only having an r-value means that it is held constant while the angle
can take on any value.
Example 4:
Change the rectangular equation
to polar form. Write the polar equation as r in terms of
.
Knowing that
, we can convert as follows:
Now, we must write the polar equation as r in terms of
. All we have to do is divide both sides of the equation by sin
.
or
(Both solutions are acceptable!)
Thus, the polar form of
is either
or
.
Example 5:
Change the polar equation
to rectangular form.
In this case, we will multiply both sides of the equation by r to get
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Knowing that
and
, we can convert as follows:
Thus, the rectangular form of
is
.
Example 6:
Change the polar equation
to rectangular form.
Since we do not have a formula that converts r to rectangular form, we will raise both sides to the second power to get
Now we can use the formula
to get
.
Thus, the rectangular form of
is
.
Example 7:
Change the polar equation
to rectangular form.
Since we do not have a formula that converts
to rectangular form, we will place the "tan" in front of both sides of the equation as follows:
We can use the formula
to get
and
or
(Both solutions are acceptable!)
Thus, the rectangular form of
is
or
.
Example 8:
Change the polar equation
to rectangular form.
Since we do not have a formula that converts secant to to rectangular form, we will use a Reciprocal Identity as follows:
Next, let's multiply both sides by
, so that we get
Knowing that
, we can convert as follows:
Thus, the rectangular form of
is
.
Example 9:
Convert the polar equation
to a rectangular equation.
Since we do not have a formula that converts r to rectangular form, we'll multiply both sides of the equation by the denominator of the term on the right of the equal sign to get
r(3
3cos
) = 1
then 3r
3rcos
= 1
and 3r = 1 + 3cos
Next, we'll square both sides to get
and given that
and
, we can now write
Thus, the rectangular form of
is 9y2 = 6x + 1.