INTRODUCTION TO ANGLES
Example 1:
Which angles are integer multiples of special angles?
Special angles are 30o, 45o, and 60o.
a. 388o
not a multiple of special angle since neither 30, nor 45, nor 60 divides into angle evenly
b. 330o
11(30o), multiple of special angle
c. 225o
5(45o), multiple of special angle
d. 119o
not a multiple of special angle since neither 30, nor 45, nor 60 divides into angle evenly
e.
120o NOTE: The negative sign only indicates that we must draw the arc of the angle in clockwise directions.
2(60o), multiple of special angle
f.
150o NOTE: The negative sign only indicates that we must draw the arc of the angle in clockwise directions.
5(30o), multiple of special angle
Example 2:
Which angles are integer multiples of special angles? Sometimes it is easier to change the angles to degrees before you decide!
Special angles are
and
and
.
a.
/8
22.5o, not a special angle
b. 5
/3
5
/3
5
60o, multiple of special angle
c. 3
/4
3
/4
3
45o, multiple of special angle
d.
/5
36o, not a special angle
e. 7
/6
7
/6
7
30o, multiple of special angle
f. 4
/9
80o, not a special angle
Example 3:
Which angles are quadrantal angles?
Remember, ALL quadrantal angles are integer multiples of 90o!
a. 388o
4(90o) + 28o , QI angle
b. 450o
5(90o), quadrantal angle
c. 720o
8(90o), quadrantal angle
d. 390o
4(90o) + 30o, QIII angle
e.
540o NOTE: The negative sign only indicates that we must draw the arc of the angle in clockwise directions.
6(90o), quadrantal angle
f.
225o NOTE: The negative sign only indicates that we must draw the arc of the angle in clockwise directions.
2(90o)
45o, QII angle
Example 4:
Which angles are quadrantal angles? Sometimes it is easier to change the angles to degrees before you decide!
Remember, ALL quadrantal angles are integer multiples of
!
a.
/8
22.5o, QI angle
b.
5
/2 NOTE: The negative sign only indicates that we must draw the arc of the angle in clockwise directions.
5
/2
5
90o, quadrantal angle
c. 3
/2
3
/2
3
90o, quadrantal angle
d. 6
/5
216o, QIII angle
e.
NOTE: The negative sign only indicates that we must draw the arc of the angle in clockwise directions.
2
/2
2
90o, quadrantal angle
Example 5:
a. Graph the quadrantal angle
90o.
b. Find the smallest positive angle in degrees that is coterminal to
90o.
It is best to graph this situation.
We quickly see that the angle with measure 270o is the smallest positive angle that is coterminal with
90o.
c. Find the smallest negative angle in degrees that is coterminal to
90o.
Please note that a negative sign simply indicates clockwise direction!
We quickly see that the angle with measure
90o +
360o =
450o is the smallest negative angle that is coterminal with
90o.
Example 6:
a. Graph the quadrantal angle 180o.
b. Find the smallest positive angle in degrees that is coterminal with 180o.
It is best to graph this situation.
We quickly see that the angle with measure 180o + 360o = 540o is the smallest positive angle that is coterminal with 180o.
c. Find the smallest negative angle in degrees that is coterminal with 180o.
Please note that a negative sign simply indicates clockwise direction!
We quickly see that the angle with measure
180o is the smallest negative angle that is coterminal with 180o.
Example 7:
Find all angles that are coterminal with a 5
/3 angle.
We can find angles that are coterminal to it by ADDING integer multiples of 2
. We will name the integer k to express ALL angles coterminal to 5
/3 as follows:
5
/3 + 2
k, where k is any integer
For instance,
when k = 2, then 5
/3 + 2
(2) = 5
/3 + 4
= 5
/3 + 12
/3 (need common denominator)
= 17
/3
when k = 1, then 5
/3 + 2
(1) = 5
/3 + 2
= 5
/3 + 6
/3 (need common denominator)
= 11
/3
when k =
1, then 5
/3 + 2
(
1) = 5
/3
2
= 5
/3
6
/3 (need common denominator)
=
/3
when k =
2, then 5
/3 + 2
(
2) = 5
/3
4
= 5
/3
12
/3 (need common denominator)
=
7
/3
Example 8:
Find an angle between 0 and 2
that is coterminal with the angle 11
/2.
We can find an angle that is coterminal to 11
/2 by SUBTRACTING from it integer multiples of 2
until the difference is smaller than 2
. This difference is a coterminal angle.
11
/2 = 8
/2 + 3
/2
= 4
+ 3
/2
= 2
+ 2
+ 3
/2
We find that 3
/2 is coterminal with 11
/2.
Example 9:
Find an angle between 0o and 360o that is coterminal with the angle 1290o.
We can find an angle that is coterminal to 1290o by SUBTRACTING from it integer multiples of 360o until the difference is smaller than 360o. This difference is a coterminal angle.
1290o = 360o(3) + 210o.
We find that the angle 210o is between 0o and 360o and is coterminal with the 1290o angle.
Example 10:
Find the location of the terminal side of the following angles. NOTE: The negative sign only indicates that we must draw the arc of the angle in clockwise directions.
Hint: Graph them!
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a. 77o - Quadrant I angle b. 77o - Quadrant IV angle
c. 125o - Quadrant II angle d. 125o - Quadrant III angle
e. 216o - Quadrant III angle f. 216o - Quadrant II angle
g. 330o - Quadrant IV angle
i. 960o = 360o(2) + 240o
Quadrant III angle using the angle 240o
which is coterminal to the angle 960oh.
330o - Quadrant I angle
j.
376o = 360o(
1) + (
16o)
Quadrant IV angle using the angle16o
which is coterminal to the angle376o
Example 11:
Find the location of the terminal side of the following angles. NOTE: The negative sign only indicates that we must draw the arc of the angle in clockwise directions.
Hint: If necessary, convert the angles to degrees, then graph them.
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|
b. |
|
d. |
|
f. |
Find the angle measures from each graph.
A.
= 360o
60o = 300o
B.
Here we must first find the angle between the terminal side of angle
and the negative x-axis. Given is 115o. We can change it to the sum of 90o and 25o. Therefore, tha angle between the terminal side of
and the negative x-axis is 25o.
Then
=
180o +25o =
155o
C.
We see that angle
has two full rotations, which equals 360o(2). Remaining is a rotation of
180o.
Then
= 360o(2) +180o = 900o
Example 13:
Find the measure of the angle below in radians. Express the angle as an improper fraction in terms of
. HINT: You can always convert to degrees to make calculations easier!
The direction of the angle is counter-clockwise. Therefore, we are dealing with a positive angle. We are counting two full rotations which is 2
+ 2
= 4
. To it we will add the measure of the arc
.
We are supposed to express the answer as an improper fraction in terms of
. When adding fractions, we need a common denominator. In our case, it is 4.
The measure of the angle in radians is
.